Ask question

Ask question

All categories

3 years ago

7

Solve the equation:

itle="\sqrt{} x^{2} + 4 - 1 = 2" alt="\sqrt{} x^{2} + 4 - 1 = 2" align="absmiddle" class="latex-formula">

1 answer:

Georgia [21]3 years ago

3 0

Answer:

D) x = √5

Step-by-step explanation:

$\sqrt{x^{2}+4 }-1 = 2$

$\sqrt{x^{2}+4 } = 3$

$x^{2}+4 = 3^{2}$

$x^{2}+4 = 9$

$x^{2} = 9 -4$

$+x = \sqrt{5} , -x = \sqrt{5}$

You might be interested in

Solve the polynomial inequality x^2-3x-10>0

djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0

3 years ago

Math: Slope help please

pishuonlain [190]

Slope = (2+5)/(-3-1) = 7/-4 = -7/4

answer is B -7/4

3 0

3 years ago

Read 2 more answers

Please tell me which are correct

Marina CMI [18]

Second, third, and fifth

4 0

3 years ago

Read 2 more answers

What is the perimeter of triangle ABC ?

blagie [28]

Answer:

$9+\sqrt{41}$

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}$

Summing it all (perimeter is sum of 3 sides):

Distance = $4+5+\sqrt{41}\\ =9+\sqrt{41}$

3rd answer choice is right.

3 0

3 years ago

topjm [15]

Answer:8,5 recirpoal is 5,8

Step-by-step explanation:

8 0

3 years ago