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ololo11 [35]
3 years ago
7

Solve the equation:

itle="\sqrt{} x^{2} + 4 - 1 = 2" alt="\sqrt{} x^{2} + 4 - 1 = 2" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

D) x = √5

Step-by-step explanation:

\sqrt{x^{2}+4 }-1 = 2

\sqrt{x^{2}+4 } = 3

x^{2}+4 = 3^{2}

x^{2}+4 = 9

x^{2} = 9 -4

+x = \sqrt{5} ,  -x = \sqrt{5}

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I forgot how to this can someone help please
Jet001 [13]

Answer:

1728

Step-by-step explanation:

You could write it like this

5.4 * 10^5 * 3.2 * 10^-3  

You could do this by multiplying the numbers first

5.4 * 3.2 = 17.28

Now work with the powers of 10

10^5 * 10^-3 = 10^(5 - 3) = 10^2

10^2 = 100

So the answer is 17.28 * 100 = 1728

3 0
3 years ago
Anotherrr Math questionn
zepelin [54]

Answer:

x=8

Step-by-step explanation:

4(x+11)=76

4x + 4(11) = 76

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4x = 76-44

4x = 32

x = 32/4

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7 0
3 years ago
Read 2 more answers
Find two consecutive odd integers such that the square of the first, added to 3 times the second is 24.
OLEGan [10]
X^2+3(X+2)=24
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3 0
3 years ago
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ch4aika [34]
The answer is 80 yes it is right

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