If the polygons are similar, then we can set up a similarity ratio using sides AB and EF and any other 2 sides where both side lengths are given. That appears to be true for sides BC and FG. Our similarity ratio would be this then, going from the bigger polygon stuff on top and the smaller polygon stuff on bottom:
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If we cross multiply we have 8y = 36 and divide both sides by 8 to get that y = 4.5. There you go!
First, let's write the given equation in slope-intercept form: y = mx + b
In slope-intercept form, the slope of the line is m, and the y-intercept is b. The slope is a measure of how steep the graph is at any point and is found by doing rise over run. This means the change in y values divided by the change in x values. Next, y-intercept is just where the graph crosses the y axis.
All we need to do to get the equation in slope-intercept form is to divide each term by 3. This will isolate the y.
As you can see, the slope of the line is 2/3, and the y-intercept is -2.
To graph the line, plot a point at (0,-2). This is the point where the graph crosses the y axis. Then from that point, count up two and right 3. Plot a point here as well. Lastly, connect the two points with a straight line.
See attached picture for the graph.
<span>Solve this by substitution:
</span>Solve 5x - 4y = -13 for x:<span><span><span><span>5x </span>− <span>4y </span></span>+ <span>4y </span></span>= -<span>13 + <span>4y </span></span></span>(Add 4y to both sides)
<span><span><u>5x </u></span>= <span><span><u>4y - </u><u>13 </u></span><u> </u> </span></span>(Divide both sides by 5)
5 5
<span>x = <span><span><span><u>4</u></span> y </span>+ -<span><u>13</u><span>
</span></span></span></span> 5 5
You can use https://www.mathpapa.com/algebra-calculator.html
5x - 4y = -13, 8x +10y = 12 (enter both equations with a comma between them and it will solve for you and show you step by step.
Answer:
See explanation below
Step-by-step explanation:
The calculations for this lottery <em>do not involve </em>the combinations rule because <em>the order of the numbers does matter</em>. For example, 1234 and 4321 are different although they have the same digits.
The calculations for this lottery <em>do involve</em> the permutations with replacement rule because any selected number can be used more than once.
By <em>the fundamental rule of counting</em>, there are 10*10*10*10 = 10,000 possible outcomes of the event with a probability 1/10,000 = 0.0001 each outcome.
I think that the ballance would be 204.40$
