All categories

3 years ago

What is the value of m

Mathematics

2 answers:

Roman55 [17]3 years ago

8 0

Answer:

m = 10

Step-by-step explanation:

From the image given, we can tell that there are two sides for angle H for the segment IJ.

From that we can see that angle H is a supplementary angle. A supplementary angle is an angle whose sum is 180°

(2m+10)°+(5m+100)° = 180°
(7m+110)° = 180°
(7m)° = 70
m = 10

harina [27]3 years ago

4 0

10 you’re welcome :)

You might be interested in

Please help, I would appreciate it a lot

AleksAgata [21]

Answer:

Sry, Can't help.

It's soo hard!!

8 0

3 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago

Plz help me with this question ASAP <br><br> Thank you so much

aniked [119]

Answer:

t1= -4

Given that result we must now find "n"

7 0

3 years ago

What is the slope of the line that passes through the points 4,3 and 9,14

vova2212 [387]

You just need your slope formula:

m = (y2 - y1)/(x2 - x1)

(4, 3) and (9, 14)
(x1, y1) and (x2, y2)

m = (14 - 3)/(9 - 4)
m = 11/5

your slope is 11/5

6 0

3 years ago

Read 2 more answers

What is the answer of this equation

Yakvenalex [24]

Can you post the rest of the question?

5 0

3 years ago