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stellarik [79]
3 years ago
6

How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup

led?
Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0
Volume of a cylinder = π r² h

Let us assume the following values:
radius = 9
height = 10

Volume = 3.14 * 9² * 10
            = 3.14 * 81 *10
Volume = 2,543.40

Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40

Volume = π r² h
             = 3.14 * 2² * 40
             = 3.14 * 4 * 40
Volume = 502.40

Original volume = 2543.40   V.S.  Volume after change = 502.40

The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times. 
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The new points are:
P' (-3, 0)
F' (1, 2)
D' (0, -2.5)

The shape is being transformed with a dilation of a scale factor of 1/2. This means that we take the given points and multiply them by 1/2 to find the new points. 

Look on the graph for the current points and multiply each one by 1/2. You will have the new points.
4 0
3 years ago
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astra-53 [7]
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2 years ago
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The Drawing of a building, shown below, has a scale of 1 inch to 30 feet. What is the Actual height, in feet, of a building?
tatyana61 [14]
Well what were given:
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The drawing of the building of this problem has the height of 1.25 inches and base of 0.75 inches.

Actual height: 
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Actual base:
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7 0
3 years ago
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its d

Step-by-step explanation:

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5 0
3 years ago
1-Andrea tenía una deuda de $25 850 en el banco y abonó $18700. ¿Cuál es su deuda<br> actualmente?
lora16 [44]

Answer:

Current debt of Andrea = $7,150

Step-by-step explanation:

Given:

Loan taken by Andrea from bank = $25,850

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Computation:

⇒ Current debt of Andrea = Loan taken by Andrea from bank - Amount paid by Andrea to bank

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Current debt of Andrea = $7,150

Note: O information provide about interest.

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3 years ago
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