1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kogti [31]
3 years ago
11

Pls help 10 points please

Mathematics
2 answers:
damaskus [11]3 years ago
5 0

<u><em>Answer: D. X=22 and 22=X. *The answer must have a positive sign.*</em></u>

Explanation:

<u><em>Addition property of equality is adding the same number to both sides of an equation </em></u><u><em>"it's does not change the equation."</em></u>

<u><em>First, add 28 both sides of an equation.</em></u>

2x-28+28=16+28

<u><em>Then, simplify.</em></u>

28+16=44

2x=44

<u><em>Next, divide by 2 both sides of an equation.</em></u>

2x/2=44/2

<u><em>And finally, simplify by equation. And divide by the numbers.</em></u>

44/2=22

22*2=44

44/22=2

2*22=44

<em><u>X=22 and 22=X</u></em>

Hope this helps!

Thanks!

Have a great day!

yaroslaw [1]3 years ago
3 0

2x - 28 = 16

Add 28 to both sides

2x = 44

Divide both sides by 2

x = 22

Answer

22

You might be interested in
What is the diameter, in meters of the circular area that gets watered by the sprinkler?
Schach [20]
The answer is 12 m.

Because you're not studying!

Next time do your mom.

3 0
3 years ago
Read 2 more answers
A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

5 0
3 years ago
What is (3.14)(87.5)²=____?
Radda [10]

Answer:

24040.625

Hope this helped! I'm not good at explaining the steps, but this is the answer.

5 0
2 years ago
What is the product of the polynomial (7x+7) (x+2)
kolbaska11 [484]

Answer: 7x^2+21x+14

Step-by-step explanation:

(7x+7)(x+2)

Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

7x×x+7x×2+7x+7×2

↘ ↙

7x×x calculate product

7x^2+7x×2+7x+7×2

↘ ↙

7x×2 calculate product

7x^2+14x+7x+7×2

↘↙

7×2 multiply numbers

7x^2+14x+7x+14

↘ ↙

21x collect like terms

7x^2+21x+14 is your end result.

3 0
3 years ago
What is the y-value when x equals 28? y=310-25(x)
Fofino [41]

Answer:

-390   PLEASE GIVE BRAINLIEST

Step-by-step explanation:

y = 310 - 25(28)

y = 310 - 700

y = -390

5 0
3 years ago
Other questions:
  • Miranda spent 1/5 of her time cooking pasta. If she spent 2 hours cooking, did Miranda spend more than, less than, or equal to 2
    14·2 answers
  • Solve -4x(6x+3)= -12(x+10)
    15·2 answers
  • Jeremy wants to verify that the transformation shown is a dilation. He finds the lengths of segments QA and AD to be 4 units.
    15·2 answers
  • Helppppp Plsssss Asap!! Thanks ​
    10·2 answers
  • Given f(x)=3x2−5x−2 .<br><br> What is the value of f(−23) ?
    10·1 answer
  • The ratio of girls to boys in a gardening club was 2:5. There were 10 girls. How many boys were there in the club?
    8·1 answer
  • The drama club was selling tickets
    8·1 answer
  • Samantha wants to know whether the food she serves in her restaurant is within a safe range of
    12·1 answer
  • Solve the equation a+b+c=180 for c
    9·1 answer
  • For khan:)<br> 2x + 5y &gt; -6<br> - 4x + 3y = 2<br> Is (-1,7) a solution of the system?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!