Answer:
t represents the time in minutes since the balloon started descending.
a(t) represents the altitude of the balloon at t minutes.
a(5.5) gives the altitude at 5.5 minutes.
Answer:
I think it is the right clock wise?
Answer:
We know that:
Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J
Energy used daily in a certain family home = 3x10^4 J
(you did not write the units, so i suppose that are the same in both cases)
Then, if x is the number of liters of solution A used, the energy produced will be:
E(x) = x*7.6x10^10 J
And we want this equal to 3x10^4
then:
E(x) = x*7.6x10^10 J = 3x10^4 j
now we solve this for x.
x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7
Then you need to use 3.9x10^-7 L of solution a.
Okay ShallBeTheLast, what we will do will involve a lot of simple plug and play kind of actions.
To start we must notice one number must be negative and the other should be positive, because the multiplied number is a negative.
Next, lets multiply number that have a sum of 10 (keep in mind one has to be negative and the other has to be positive).
-1 * 10 = -10 false
-2 * 12 = -24 false
-3 * 13 = -39 false
notice that no number working and it's only getting farther away.
There is no solution for this that involves to integers.
I think you might of wrote the question backwards.
If that is the case we would run numbers like.....
-1 * (-6) = 7 false
-2 * (-5) = 10 true!!!!
-2 and -5 would work
Answer: 13&7
Step-by-step explanation:
The sum of two numbers x&y is 20
Product of the 2numbers xy is 51
X+y=20......equation 1
XY=51.........equation 2
X=20-y.......equation 3
Substitute for x inequation 3 into equation 2
So we have;
(20-y)y=51
Open the bracket
20y-y^2=51
Collect like terms,so we have
Y2-20y+51=0
Factorise
Factors of 51 is 13&7
So -13-7=-20 &-13×-7=51
Substitute
Y2-13y-7y+51=0
Y(y-13)-7(y-13)=0
(Y-7)(y-13)=0
Y-7=0
Y=7 or
Y-13=0
Y=13
Y=13 or 7
Substitute for y in equation 1
X+y=20
X+7=20
X=20-7
X=13 or
X+13=20
X=20-13
X=7
Therefore, X &Y = 13 &7
