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Gwar [14]
3 years ago
10

Help pleasee!!! Tyyyyy

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

G. 7

Explanation:

The longest side must be less than the sum of the two shorter sides.

The difference between the longest and shortest sides must be less than the middle side.

l+a = 11

l < (a + 4) ... l < (11 - l + 4)

... 2 l < 15 ... l <  7.5

--Variables

l = 7 (Longest Side/Answer)

a = 4 (Other Missing Length)

m = 4 (Side Given)

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Inverse function of y=f(x)=1-2/x^3
tia_tia [17]

Answer:

not sure

Step-by-step explanation:  not good at this stuf



6 0
3 years ago
A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
12 – 2x= -2(y – x)<br> -2x = -2(y – x) – 12<br> x= (y - x) + 6
Vilka [71]

Answer:

x=o and y= -6

Step-by-step explanation:

12-2x = - 2(y-x)

or,12-2x = -2y + 2x

or, 12 = - 2y + 4x

or, 12/2= 2x - y

or, 2x - y = 6

• 2x -6= y.....eqn_1

-2x=-2y+2x -12

or,4x +2y= -12

or,4x + 2(2x-6)= -12

or, 4x+4x-12=-12

or, 8x= 0

• x= o

putting the value of x in eqn...3

o=(y-0)+6

or, o= y + 6

•y = -6

5 0
3 years ago
How do I show the work where 69 miles per hours is proportional to the number of hours
riadik2000 [5.3K]
<span>1. First, label the axis on your graph, with units:

time on the x-axis, in units of hours;

distance on the y-axis, in units of miles.

2. Draw a graph of distance vs. time. Distance after the first hour = 69 miles, distance after the 2nd hour = 138 miles, etc.

3. Observe that this graph is a STRAIGHT LINE with constant slope. Therefore the relationship is PROPORTIONAL.

For every other kind of graph -- i.e. not a straight line -- the relationship is NON-PROPORTIONAL.

Hope this helps. </span>
6 0
3 years ago
Solve for c; a/b+c=d/c
Eduardwww [97]

To solve for c, you need to get c onto one side of the equation, or make it c=__. So what I would do first is subtract a/b from both sides

a/b + c = d/c

-a/b

a/b - a/b + c = d/c - a/b

c = d/c-a/b

8 0
3 years ago
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