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4 years ago

I got the answer as letter C, can someone check me to make sure that is correct? Thank you in advance.

Mathematics

1 answer:

Flura [38]4 years ago

3 0

Answer:

The x's cancel so definitely is choice C: 1/9

Step-by-step explanation:

We have root( 1/(x^2) ) * root ((x^2) / 81)

simplifying this we get as follows:

root( 1/(x^2) ) * root ((x^2) / 81)

= $\sqrt{(1/x^2 )}$ * $\sqrt{(x^2)/81}$

= ( 1/x ) * (x/9)

the x's cancel

= 1/9

choice C 1/9

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Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2

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Answer:

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Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3 $\pi$ /2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

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= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]$

= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]$

= ${\frac{10 }{3\pi }}[ {1 - 0 } ]$

= ${\frac{10 }{3\pi }$

⇒ $f_{ave}$ = ${\frac{10 }{3\pi }$

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