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Gemiola [76]
3 years ago
5

A corner store sells two kinds of baked goods: cakes and pies. A cake costs $7 and a pie costs $6. In one day, the store sold 10

baked goods for a total of $66. What system would work for the situation?
Mathematics
1 answer:
kondaur [170]3 years ago
4 0

9514 1404 393

Answer:

  • c + p = 10
  • 7c + 6p = 66

Step-by-step explanation:

Assuming you're interested in the number of each that were sold, the system of equations will express the relation for total sold, and the relation for total revenue. We have used the variable c and p to represent numbers of cakes and pies sold, respectively. Your choices may use x and y, instead.

  • c + p = 10
  • 7c + 6p = 66

__

The solution can be found by subtracting 6 times the first equation from the second. That tells you 6 cakes were sold, hence 4 pies.

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Answer:

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Step-by-step explanation:

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algol13

Completed question:

In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?

Answer:

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Step-by-step explanation:

For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:

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Answer:

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Step-by-step explanation:

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