S=d/t ⇒d=s*t
s=speed
d=distance
t=time
The first train :
d=x
x=70 miles/h*t ⇒ x=70t (1)
The second train
d=360 miles - x
360 miles - x=80 miles/h*t ⇒360-x=80t ⇒ x=360-80t (2)
therefore, with the equations (1) and (2) we have a systeme of equations:
x=70t
x=360-80t
we can solve this system of equations by equalization method.
70t=360-80t
70t+80t=360
150t=360
t=360/150=2.4 (≈2 hour 24 minutes)
Answer: the first train meet with the second train in 2 hour 24 minutes.
Complete question :
Tom will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $57.98 and costs an additional $0.14 per mile driven. The second plan has an initial fee of $53.98 and costs an additional $0.16 per mile driven. How many miles would Tom need to drive for the two plans to cost the same?
Answer:
200 miles
Step-by-step explanation:
Let miles driven = x
First option :
57.98 + 0.14x
Second option :
53.98 + 0.16x
First option = second option
57.98 + 0.14 = 53.98 + 0.16x
57.98 - 53.98 = 0.16x - 0.14x
4 = 0.02x
x = 200
200 miles
Put the equations in for r and c
p(c)=10x-(4x+15)
put the negaive in
10x-4x-15
6x-15
Answer is C
If the temperature was 3 degrees Fahrenheit at Midnight, and it dropped 7 degrees during the next hour, then the temperature at 1 A.M. would be -4 degrees Fahrenheit. This is true because 3 - 7 = -4.
So, the answer to this question is that the temperature was -4 degrees Fahrenheit at 1 A.M.
Answer:
153 miles
Step-by-step explanation:
36 * 4.25 = 153
