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3 years ago

Evaluate the expression if f = 16,8 = 4 and h = 2. fxg:h

Mathematics

1 answer:

Eduardwww [97]3 years ago

7 0

It would be h = 2 if you are trynna figure out what H is

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Suppose DK is an angle bisector of △DEF. <br><br><br>Given: EK=2, FK=5, DF=10. Find DE.

ziro4ka [17]

Answer:

$DE=4$

Step-by-step explanation:

We have been provided a graph of a triangle and we are asked to find the length of segment DE.

Angle bisector theorem states that if a ray bisects an angle of a triangle, then it bisects the opposite side of triangle into segments that are proportional to other two sides.

By angle bisector theorem we can set proportions of the given sides as:

$\frac{DE}{EK}=\frac{DF}{FK}$

Upon substituting our given values in above proportion we will get,

$\frac{DE}{2}=\frac{10}{5}$

Upon multiplying both sides of our equation by 2 we will get,

$\frac{DE}{2}\times 2=2\times \frac{10}{5}$

$DE=2\times 2$

$DE=4$

Therefore, the length of segment DE is 4 units.

5 0

4 years ago

Question 3(Multiple Choice Worth 5 points) (06.08A) Simplify negative 15.5 divided by 5 .. −3.1 3.1 −3.3 3.3

xz_007 [3.2K]

A negative divided by a positive gives a negative result

So the answer is -3.1

Hope this helps!

3 0

3 years ago

Read 2 more answers

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

MrMuchimi

Answer:

attached below

Step-by-step explanation:

6 0

3 years ago

What is the perimeter of the parallelogram?

Nesterboy [21]

P=2(a+b)=2·(4+4)=16 cm

3 0

3 years ago

1. Type an equation in the equation editor that uses 2 fractions with parentheses around one of them. Example: <img src="https:/

avanturin [10]

Answer:

i) $\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}$ $\Rightarrow$ \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii) $4^{3} + 8^{2} + \sqrt{9}$ $\Rightarrow$ 4^{3} + 8^{2} + \sqrt{9}

iii) $(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}$ (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) $\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}$ $\Rightarrow$ \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii) $4^{3} + 8^{2} + \sqrt{9}$ $\Rightarrow$ 4^{3} + 8^{2} + \sqrt{9}

iii) $(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}$ (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

7 0

3 years ago