Answer:
5:7
5/7
5 to 7
10:14 --> 10x2=20 14x2=28
20:28 --> 20x2=40 28x2=56
40:56
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
As shown in the model below, there are three lines.
Answer:
x=9
Step-by-step explanation:
2x+12=5x-15
3x=27
x=9
Given :
Ruth wants to buy a skateboard for $44.
She has $100 in her account. She spent $11.36 to buy stationary.
She also wants to buy some comic books for $3.72 each.
To Find :
The maximum number of comic books, n, that Ruth can buy so that she has enough money left to buy the skateboard.
Solution :
Money left after buying skateboard and stationary is :
Money left = $(100 - 11.36 - 44)
Money left = $44.64
Number of comic she can buy is :
Therefore, she can buy a maximum of 12 books.
Hence, this is the required solution.
