Answer:
18 inches and 9 inches
Step-by-step explanation:
Given, The base of a triangle is twice of the height.
Area = 81 sq inches
Let, Base (b) = 2x
Height (h) = x
Area of the triangle = \frac{1}{2}bh
\frac{1}{2}bh = 81
or, x^{2} = 8
Base = 2×9 inches = 18 inches
Height = 9 inches
Answer:
C.) x= -4
Step-by-step explanation:
just took the test on edg. 2020
Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:
![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)
Answer:
270m^3
Step-by-step explanation:
Area of the base times Hight. 9*5= 45 area of base 45*6= 270m
Algebraically, that will be expressed as:
