All categories

3 years ago

If y=2 what is the value of 8y

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

3 0

Answer:

Step-by-step explanation:

y=2 so just place the variable (y) in 8y with 2

8(2)=16

You might be interested in

A college president says, "More than two-thirds of the alumni support my firing of Coach Boggs." The president's statement is ba

FrozenT [24]

The answer to this is A

6 0

3 years ago

You are downloading a song. The percent y (in decimal form) of megabytes remaining to download after x seconds is; y=-0.1x+1. If

pychu [463]

Y = -0.1x+1
0.5 = <span>-0.1x+1
-0.5 = -0.1x
x = 5
It takes 5 seconds for the download to be 50% complete.

</span>

7 0

3 years ago

Read 2 more answers

A classmate simplified a rational expression below

lara31 [8.8K]

<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$\:1-2x-4=x^2-x-2$

$-2x-3=x^2-x-2\:\:$

$0=x^2-2x-2\:\:$

$0=\left(x-1\right)\left(x-1\right)$

$x=1$

<u><em>Identifying the Main Error</em></u>

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$ ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u> $\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)$ <em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$x^2-2x-8=x^2-x-2$

$x^2-2x-8+8=x^2-x-2+8$

$x^2-2x=x^2-x+6$

$-x=6$

$\frac{-x}{-1}=\frac{6}{-1}$

$x=-6$

3 0

3 years ago

What is the circumference and area of this circle? (Use 3.14 for pi)

Aloiza [94]

37.7 i think it would be

3 0

3 years ago

Help Picture below ..........

Nataly_w [17]

Answer:

Step-by-step explanation:

Multiply them according to the problem.

$6x+2y=6 \\ \\ -3(6x+2y)=(6)*-3 \\ \\ -18x-6y=-18 \\ \\ \\ 7x+3y=9 \\ \\ 2(7x+3y)=(9)*2 \\ \\ 14x+6y=18$

As you can see, the only terms in the two equations that can cancel out are $-6y$ and $6y$ .

3 0

3 years ago

If y=2 what is the value of 8y​

If y=2 what is the value of 8y