The base of a rectangular prism is 20 cm2. If the height of the prism is 5 cm, what is its volume?

Find center and radius (x-3)^2+y^2=8

Flauer [41]

Answer:

<h2>Center: (3, 0)</h2><h2>Radius: 2√2</h2>

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the equation:

$(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2$

Therefore

the center: $(3,\ 0)$

the radius: $r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2$

4 0

2 years ago

14. Find mMK please :)

MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14) strategy: find the angle at L, and that will also be the arc of MK

copy and past the below helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

copy and past the above :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15) strategy: arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°

arc JPK = 253.7397°

7 0

2 years ago

PLS HURRY THIS IS REALLY HARD FOR ME(CLICK AND PINCH TO SEE ALL OR TO SEE CLOSE)Wrong subjact it English

Elanso [62]

Answer:

1. were living past

2. are playing present

3.were laughing past

4.is coming present

5. are talking present

6. are hiring present

7.am hiring present

8.are bullying present

9. are training present

10. were growing past

Step-by-step explanation:

6 0

3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height y = 5 ft and a standard

Arisa [49]

Answer: Fourth Option:

"A tree with a height of 6.2 ft is 3 standard deviations above the mean"

Step-by-step explanation:

It is said that an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have that:

$\mu=5\ ft$

$\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For $X =5.4\ ft$

$Z=\frac{X-\mu}{\sigma}$

$Z=\frac{5.4-5}{0.4}=1$

This means that: A tree with a height of 5.4 ft is 1 standard deviation above the mean

First Option: False

For $X =4.6\ ft$

$Z=\frac{X-\mu}{\sigma}$

$Z=\frac{4.6-5}{0.4}=-1$

This means that: A tree with a height of 4.6 ft is 1 standard deviation below the mean

Second Option: False

For $X =5.8\ ft$

$Z=\frac{X-\mu}{\sigma}$

$Z=\frac{5.8-5}{0.4}=2$

This means that: A tree with a height of 5.8 ft is 2 standard deviation above the mean

Third Option: False

For $X =6.2\ ft$

$Z=\frac{X-\mu}{\sigma}$

$Z=\frac{6.2-5}{0.4}=3$

This means that: A tree with a height of 6.2 ft is 3 standard deviations above the mean.

Fourth Option: True

3 0

3 years ago

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Dawn is going scuba diving. Which situation would be modeled by a positive number?

NemiM [27]

Answer:

Once Dawn is going going back to sea level.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers