All categories

3 years ago

How do you turn a mix number into a fraction?

Mathematics

2 answers:

Lilit [14]3 years ago

6 0

By multiplying the denominator and while number them adding the numerator so 5 6/8 Is equal to 46/8

Tomtit [17]3 years ago

5 0

You must add or subtract, depending on which fraction your going for at that time.

You might be interested in

Find the measure of <_BCA.

forsale [732]

<BCA+<BCD=180°

m<BCD=116°

<BCA+116°=180°

m<BCA=64°

6 0

3 years ago

Match the numerical expressions to their simplest forms

zimovet [89]

I hope you did well on this question.

6 0

3 years ago

A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and se

topjm [15]

If the probability of the first sock is red and their are 10 socks in total (same with the second sock). they should both add up to 2/20 probability chance.

3 0

3 years ago

A researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean time (8.1) it takes for a dr

Sergio039 [100]

Answer:

For this case we know that the confidence interval is given by (1.2 , 1.8) and the point of estimate for $\mu$ would be:

$\bar X = \frac{1.2+1.8}{2}= 1.5$

And the margin of error is given by:

$ME = \frac{1.8-1.2}{2}= 0.3$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case we know that the confidence interval is given by (1.2 , 1.8) and the point of estimate for $\mu$ would be:

$\bar X = \frac{1.2+1.8}{2}= 1.5$

And the margin of error is given by:

$ME = \frac{1.8-1.2}{2}= 0.3$

6 0

4 years ago

A car rental company's standard charge includes an initial fee plus an additional fee for each mile driven. The standard charge

Radda [10]

4 days later. ugh haha sorry. answer in the first ten min on time my butt

7 0

3 years ago