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Vitek1552 [10]
3 years ago
5

Chris buys a car for $24,000. If the car loses value at a rate of 9% per year, what will it be worth in 5 years? Round to the ne

arest dollar.
Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0
A=p(1-r)^n
A=24,000×(1−0.09)^(5)
A=14,976.77
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a_sh-v [17]

Answer: i think its B not sure tho.

Step-by-step explanation:

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2 years ago
32 + 4 (2 + 4) X 6 = 8 + 4 =
Svetradugi [14.3K]

Answer:

176=12

Step-by-step explanation:

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A cyclist cycles a distance of 40 miles in a time of 2 hours. what is her average speed?
snow_lady [41]

Answer:

see this and it by your own

Step-by-step explanation:

How do you find average speed with distance and time?

Divide the distance by the time.

This will give you the average speed per unit of time, usually hour. So, if Ben traveled 150 miles in 3 hours, his average speed is 50 miles per hour

How do you find average speed with hours and minutes?

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3 years ago
Help! I'll give brainy
Ne4ueva [31]
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5 0
2 years ago
Read 2 more answers
Laura lives 15 miles east of Kevin’s place. Kevin lives 8 miles south of Michelle’s place. How far does Michelle live from Laura
My name is Ann [436]

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi)  =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

D = \sqrt{(a - c)^2 + (b - d)^2}

Then the distance between  (-15mi, 8mi) and (0mi, 0mi) is:

D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi

The correct option is the first one, 17 miles.

6 0
3 years ago
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