Answer:
The minimum distance x that a plant needing full sun can be placed from a fence that is 5 feet high is 4.435 ft
Step-by-step explanation:
Here we have the lowest angle of elevation of the sun given as 27.5° and the height of the fence is 5 feet.
We will then find the position to place the plant where the suns rays can get to the base of the plant
Note that the fence is in between the sun and the plant, therefore we have
Height of fence = 5 ft.
Angle of location x from the fence = lowest angle of elevation of the sun, θ
This forms a right angled triangle with the fence as the height and the location of the plant as the base
Therefore, the length of the base is given as
Height × cos θ
= 5 ft × cos 27.5° = 4.435 ft
The plant should be placed at a location x = 4.435 ft from the fence.
Answer:
19 degrees
Step-by-step explanation:
From the question given
The interior angles are x+12 and x - 3
Exterior angle is <IJK = 5x-6
Using the rule that states that the sum of interior angle of a triangle is equal to the exterior
<JHI + <HIJ = <IJK
x+12 + x-3 = 5x - 6
2x+9 = 5x -6
2x - 5x = -6-9
-3x = -15
x = -15/-3
x = 5
Get <IJK
Recall that <IJK = 5x - 6
<IJK = 5(5) - 6
<IJK = 25-6
<IJK = 19 degrees
Hence the measure of <IJK is 19 degrees
Answer: -5/21
Step-by-step explanation:
-3/7 & -4/6
common detonator is 42
-3/7 = -18/42 reduced to -9/21
-4/6 = -28/42 reduced to -14/21
difference between -9/21 and -14/21 = -5/21
