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Veronika [31]
3 years ago
7

PLEASE HELP!! I WILL NAME THE BRAINLEST!!!!

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Where is the table at


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What is the formula for the area of:
Paul [167]

Answer:

Triangle- (height × base)/2

Rhombus-(First diagonal×Second diagonal)/2

Trapezoid- (First base+second base)/2×height

N-gon= (Side-2)*180

8 0
3 years ago
Read 2 more answers
Jennifer went shopping at the
DiKsa [7]

Answer:

She bought 2 long sleeve shirts and 4 t-shirts

Step-by-step explanation:

Let number of long sleeves = x

Let number of t-shirts = y

x+y=6

∴y=6-x

14x+4y=44

14x+4(6-x)=44

14x+24-4x=44

10x=20

x=2

y=6-x

=6-2=4

ANS: She bought 2 long sleeve shirts and 4 t-shirts

4 0
3 years ago
Read 2 more answers
PLEASE HELP ITS URGENT! Put the X numbers in the X area then solve! THANK LY!
pishuonlain [190]
You just take your rule y=4x-1 and plug it in for your y ex:-4(-5)-1=19 like that just plug it in for others
3 0
4 years ago
What is the value of x to the nearest tenth?
natka813 [3]
X = 2.1 x tan(37)

x = 1.58 = 1.6
5 0
3 years ago
Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented
sp2606 [1]

Answer:  The answer is A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


Step-by-step explanation: Given that the area of the whole circle is represented by the expression

A_c=25x^2-12x-9.

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.

Thus, the area of the outer ring is

A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


5 0
4 years ago
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