4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
m = -2
y-intercept = 4
Step-by-step explanation:
m = y2-y1/x2-x1
so
m = -2-4/3-0
=-2
y=mx+b
Substitute the coordinates into the equation to find b
4=-2(0)+b
4=b
so y intercept is 4
y=-2x+4
The answer is 13/85. You could find out the answer by doing the reprical multiplication.
Answer:
B
Step-by-step explanation:
To go from 6 to 9 you'd first have to divide 6 by 2 and the multiply by 3,
so 
x 3 = 
