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4 years ago

It is possible that the universe may

1 answer:

7 0

<span>B. explode within the next million years.
C. continue to expand forever.
D. dissipate from lack of sufficient matter. </span>

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A railroad freight car rolls on a track at 3.50 m/s toward two identical coupled freight cars, which are rolling in the same dir

ladessa [460]

Answer:

Explanation:

Hello! To solve this problem we must be clear about the concept of energy conservation, and kinetic energy with the following sentence

The kinetic energy of the two cars (v = 1.2m / S) plus the kinetic energy of the third car (v = 3.5m / S) must be equal to the kinetic energy of the three cars together.

The kinetic energy is calculated by the following equation.

$E=0.5mV^2$

m= mass of the cars=26500kg

V=speed

E=kinetic energy

taking into account the above, the following equation is inferred

1= the cars are separated

2= the cars are togheter

E1=E2

$E1=0.5mV1^2+0.5mV1^2+0.5m(Va)^2$

where

m= mass of each car

V1= 1.2m/s

Va=3.5,m/S

$E2=0.5(3)(m)V^2$

m= mass of each car

V=speed (in m/s) of the three coupled cars after the first couples with the other two

Solving

$0.5mV1^2+0.5mV1^2+0.5m(Va)^2=0.5(3)(m)V^2$

$V1^2+V1^2+(Va)^2=(3)V^2.\\2V1^2+(Va)^2=(3)V^2\\V^2=\frac{2V1^2+(Va)^2}{3} \\$

$V=\sqrt{\frac{2V1^2+(Va)^2}{3}} \\V=\sqrt{\frac{2(1.2)^2+(3.5)^2}{3}} \\\\V=2.245m/s$

the speed of the three coupled cars after the first couples with the other two is 2.245m/s

7 0

4 years ago

Read 2 more answers

L 1.3.5 Quiz: Using Models

arsen [322]

Answer:

0.12 is correct

Explanation:

1:25=1/25

1/25x3=

3/25=0.12:)

8 0

3 years ago

star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?

goldenfox [79]

Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.

<h3>What is stellar parallax and distance measurement using stellar parallax?</h3>

To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.

A straightforward correlation exists between the distance of a star and parallax angle:

$d=\frac{1}{p}$

The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.

Stellar parallax of star A= 0.58 arcseconds

Stellar parallax of star B= 0.73 arcseconds

So, on applying the formula,

The distance of the star A= 1.72pc

And the distance of the star B= 1.36pc

Therefore, star B is closer than star A.

To know more about stellar parallax, visit:

brainly.com/question/29352944

#SPJ4

3 0

1 year ago

A thin film of oil (n = 1.27) is located on smooth, wet pavement. When viewed from a direction perpendicular to the pavement, th

alisha [4.7K]

Answer:

Explanation:

The problem is based on interference in thin films

refractive index of water is more than given oil so there will be phase change of π at upper and lower layer of the film .

a )

for constructive interference , the condition is

2μt = nλ where t is thickness of layer , μ is refractive index , λ is wavelength and n is order of the fringe

Putting the values

2 x 1.27 t = n x 640

2 x 1.27 t = 640 ( for minimum thickness n = 1 )

t = 252 nm .

b )

2 x 1.27 t = m₁ λ₁

for destructive interference

2μt = (2m₂+1)λ₂/2

2 x 1.27 t =(2m₂+1)λ₂/2

m₁ λ₁ = (2m₂+1)λ₂/2

2m₁λ₁ = (2m₂+1)λ₂

2m₁ / (2m₂+1) = λ₂ / λ₁

2m₁ / (2m₂+1) = 548/ 640

2m₁ / (2m₂+1) = .85625

2m₁ = .85625 (2m₂+1)

This is the required relation between m₁ and m₂

6 0

4 years ago

Insurance can help you

RUDIKE [14]

I dont know if insurance can help u sweeid

7 0

3 years ago