The force of friction on the box is 8.82 N.
The force of friction is given by the formula
F=μN
Here N is the normal force of the box=mg=3*9.8=29.4 N
Now the static friction force on the box is=0.4*29.4=11.76 N
Since the box is applied with the horizontal pull of 15 N, which is greater than the static friction, therefore the box must be in the moving condition, in that case there is dynamic friction force is applied on the box=0.3*29.4=8.8 N
Therefore the force of friction on the box is 8.8 N.
Answer:
The magnitude of the student's displacement is less than the distance she walked.
Walking: 11 Blocks
Displacement: 8.54 Blocks
Explanation:
See the attached diagram. The unit of length is blocks. We can add the actual blocks walked as shown. She walked a total of 11 blocks.
Her displacement is the distance measured directly from where she started (line A). Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines. The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.
That result is 8.54 Blocks, a shorter distance, once she earns her wings.
Fallout is awesome, but I didn't care too much for the base building mainly because of the amount of time it takes to make it perfect.
Explanation:
(a) Velocity is given by :
s is the length of the distance
t is the time
The dimension of v will be,
(b) The acceleration is given by :
v is the velocity
t is the time
The dimension of a will be,
(c) Since,
(d) Since,
(e)
Hence, this is the required solution.