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Elodia [21]
2 years ago
14

How many main retrofit strategies help solve the ecological problems with suburbs?

Physics
1 answer:
iragen [17]2 years ago
3 0

ANSWER:

5

Explanation:

Because they are elven in numbers

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What is the current if a charge of 25 coulombs passes in 5 seconds?
Jobisdone [24]

Answer: 5 amps

Explanation: I = Q/t

8 0
3 years ago
What is the difference between a hurricane and a typhoon
Lera25 [3.4K]

Answer:

The answer is below

Explanation:

Well, a hurricane is a storm with violent winds (more less with a force of 12 in the scale that measures winds) and it happens especially in the Caribbean sea. While a typhoon is also a strong storm but it happens especially in the Indian region and the western pacific oceans.

In conclusion, their difference is the area in which they happen.

3 0
3 years ago
What are three elements that are in the same group
cluponka [151]
Iodine, chloride, and bromide
3 0
2 years ago
Consider the following equations of motion.
Helen [10]

A) No, the equations presented above are the product of the derivation of position and velocity when the acceleration is constant.

The equations change to polynomial function of the second degree for the description of the acceleration when described as a function of time.

B) Yes, when the acceleration is zero it is concluded that the velocity is constant, therefore they could be used to describe the position as a function of the change in velocity.

6 0
3 years ago
A positively charged wire with uniform charge density +λ lies along the x-axis and a negatively charged wire with uniform charge
Kisachek [45]

Answer:

\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

Explanation:

The electric field created by an infinitely long wire can be found by Gauss' Law.

\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E2\pi r h = \frac{\lambda h}{\epsilon_0}\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 r} \^r

For the electric field at point (x,y), the superposition of electric fields created by both lines should be calculated. The distance 'r' for the first wire is equal to 'y', and equal to 'x' for the second wire.

\vec{E} = \vec{E}_1 + \vec{E}_2 = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) + \frac{-\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) - \frac{\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

5 0
3 years ago
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