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fomenos
3 years ago
11

It is 6 kilometers from chris's house to the nearest mailbox. how far is it in meters

Mathematics
1 answer:
mote1985 [20]3 years ago
8 0
6 kilometers = 6000 meters


1 kilometer = 1000 meters
So, 1000 × 6
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Match each set of vertices with the type of quadrilateral they form.
Serjik [45]
Only correct the first one.

Please, see the graph in the attached file.

1) a rectangle with                   A(3,3), B(3,6),
    noncongruent          ←→     C(7,6), D(7,3)
    adjacent sides
    (in green)

2) a parallelogram                  
    with                                       A(2,0), B(3,2) 
    nonperpendicular     ←→     C(6,3), D(5,1)
    adjacent sides
    (in blue)

3) a square                  ←→       A(3,3), B(2,5),
    (in red)                                   C(4,6), D(5,4)

4) a rhombus with                    A(2,-2), B(3,0),
    nonperpendicular    ←→     C(4,-2), D(3,-4)
    adjacent sides
    (in black)

5 0
3 years ago
Which values for x, y, and z satisfy the equation 7xy/z=28
nirvana33 [79]

Answer:

try x= 4z/y

Step-by-step explanation:

7 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Which expression is equivalent to 6f+f?
Elena L [17]

Answer:

A

Step-by-step explanation:

This is because 6f+f is just 7f.

f f f f f f+f = fffffff

Soooo, ONLY A gives us 7f when added together again.

f+5f+f=7f.

f+ f f f f f +f = fffffff

3 0
2 years ago
Read 2 more answers
A skirt costs $20 more than the blouse. the skirt costs $65. what is the price of the blouse. write an equation. then solve the
Aleksandr [31]
$65 -  $20
=$45

$65=the skirt

$45=the blouse
8 0
3 years ago
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