Gregory may choose between two accounts in which to invest $5000. Account A offers 2.3% annual interest compounded monthly. Acco
unt B offers continuous compound interest. Greg plans to leave his investment untouched (no further deposits and no withdrawals) for 10 years.
need help calculating account b's balance
need help calculating account b's balance
1 answer:
Answer:
<h2>Gregory should take the continuos compound interest.</h2>Step-by-step explanation:
If we calculate the Amount with both type of interest, we have:
Annual interest compounded monthly:
This means that with this interest, after 10 years he will get $6,291.61.
Continuous compound interest:
Meaning that Gregory will get 6,293.
As you can see, it's not a big difference, only $2 more, but it's still better.
<em>(Image attached are formulas with the variables meanings)</em>
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Answer:
- h ≥ 0
- C = 0; concentration eventually decays to nothing
- (0, 0) is the only intercept in the domain. It means the concentration in the bloodstream is zero at the time the drug is injected.
- 1.95 hours
Step-by-step explanation:
1. a. The domain of the function in the context of this problem is h ≥ 0. The maximum value of h will correspond to the time at which the concentration is considered to be negligible. If that time is when the concentration decays to 1% of its peak value, then perhaps the suitable domain is 0 ≤ h ≤ 180.
b. The equation of the vertical asymptote of this function is where the denominator of C(h) is zero, that is ...
h^3 +8 = 0
h = ∛(-8)
h = -2 . . . . the equation of the vertical asymptote
This is not a concern for a medical professional because it is outside the domain of the function.
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2. As h gets large the value of the function approaches 2/h, which is to say the horizontal asymptote is C = 0. It means the concentration of medication in the blood eventually decays to zero.
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3. C(0) = 0 is the only intercept in the domain of the function. (h, C(h)) = (0, 0)
In the context of this problem, it means the blood concentration of medication is zero at the time of the injection.
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4. About 1.95 hours after injection, a maximum concentration of the drug occur in the bloodstream. This value is easily found using a graphing calculator.
Taking the derivative of the function gives you ...
C'(h) = -2(h^4 +5h^3 -16h -20)/(h^3 +8)^2
This has two real zeros and two complex zeros. The positive real zero is near h = 1.94527, about 1.95.
That is, the concentration in the bloodstream reaches a maximum about 1.95 hours after injection into the muscle.
