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andre [41]
3 years ago
11

Gregory may choose between two accounts in which to invest $5000. Account A offers 2.3% annual interest compounded monthly. Acco

unt B offers continuous compound interest. Greg plans to leave his investment untouched (no further deposits and no withdrawals) for 10 years.
need help calculating account b's balance

Mathematics
1 answer:
evablogger [386]3 years ago
3 0

Answer:

<h2>Gregory should take the continuos compound interest.</h2>

Step-by-step explanation:

If we calculate the Amount with both type of interest, we have:

Annual interest compounded monthly:

A=P(1+\frac{r}{n} )^{nt} \\A=5000(1+\frac{0.023}{12} )^{12(10)} \\A=6291.61

This means that with this interest, after 10 years he will get $6,291.61.

Continuous compound interest:

A=Pe^{rt} \\A=5000e^{0.023(10)} \\A=6293

Meaning that Gregory will get 6,293.

As you can see, it's not a big difference, only $2 more, but it's still better.

<em>(Image attached are formulas with the variables meanings)</em>

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Part A: after 9 days the radius of the algae would be 12.81mm so the domain is 9. you would plot the domain at (0,9)

Part B: the y-intercept (the 9) represents the amount of algae the experiment started off with.

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Step-by-step explanation:

4 0
3 years ago
Solve each equation and leave the answer in terms of “i”
almond37 [142]
17)
x² + 8 = -8
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x² = 16
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Is y= x2-1 a linear equation
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3 years ago
A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0
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