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katen-ka-za [31]
3 years ago
15

Chad has a rope that is 20 yards long. How many pieces of rope measuring 4/7 of a yard can he divide his rope into?

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

35\ pieces

Step-by-step explanation:

we know that

To find the number of pieces of rope 4/7 of a yard, divide the total length of the rope by 4/7

we have that

The total length of the rope is 20 yards

so

\frac{20}{(4/7)}=\frac{20*7}{4}=35\ pieces

gogolik [260]3 years ago
4 0

Answer:

28 is the answer

Step-by-step explanation:

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A Yamaha dirt bike has a sticker price of
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Answer:

1353.13

Step-by-step explanation:

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then round to the hundredths place to get 1353.13

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4 0
3 years ago
Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
Elan Coil [88]

Answer:

(40/3)*pi

Step-by-step explanation:

lets first find the area of the little circle

A=pi*r^2

A=pi*3^2

A=9pi

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A=pi*r^2

A=pi*(3+4)^2

A=pi*7^2

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now lets subtract the area of the little circle from the area of the big circle

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4 0
3 years ago
The number of pizzas ordered on friday evenings between 5:30 and 6:30 at a pizza delivery location for the last 10 weeks is show
Ainat [17]
For a smoothing constant of 0.2

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90

Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12

The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80

Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17

The mean forecast for period 11 is 53.56


Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
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