3 years ago

3(-2a-4)+3a what would this be i have so many questions today to ask y'all

Mathematics

2 answers:

Novay_Z [31]3 years ago

8 0

Answer:

Solution,

$3( - 2a - 4) + 3a \\ = 3 \times ( - 2a) - 3 \times 4 + 3a \\ = - 6a - 12 + 3a \\ = - 6a + 3a - 12 \\ = - 3a - 12 \\ = - 3(a + 4)$

Hope this helps...

Good luck on your assignment...

ololo11 [35]3 years ago

5 0

Answer:

-3(a+4)

Step-by-step explanation:

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The magnitude, M, of an earthquake is defined to be M=log I/S, where I is the intensity of the earthquake (measured by the ampli

GarryVolchara [31]

Answer:

Step-by-step explanation:

Magnitude $M$ of an earthquake is defined as $M=log\text{ }\frac{I}{S}$ . Here $I$ is the Intensity of the earthquake and $S$ is the intensity of standard earthquake.

We have an earthquake that is 10 times more intense than a standard earthquake. Let us denote the intensity of the earthquake as $I$ .

10 times more intense than standard earthquake ⇒ $I=10S$

Magnitude of the earthquake = $M\text{ = }log\text{ }\dfrac{I}{S}\text{ = }log\text{ }\dfrac{10S}{S}\text{ = }log\text{ }10\text{ = }log_{10}\text{ }10\text{ = }1$