The point (-2, 5) is not included in the solution area
<h3>The graph of the inequalities</h3>
The system of inequalities is given as:
y > 5x + 5
y > -2x+1
See attachment for the graph.
Since the inequalities use the greater than symbol, then the lines of the inequalities would be a dotted line and the upper part would be shaded
<h3>The solution area</h3>
The point is given as:
(-2, 5)
The point (-2, 5) is not in the shaded area of the system of inequalities
Hence, the point is not included in the solution area
Mathematically, we have:
5 > 5 * -2 + 5 ⇒ 5 > -5 --- true
5 > -2 * -2 +1 ⇒ 5 > 5 --- false
Since both inequalities are not true, then the point is justified
Read more about system of inequalities at:
brainly.com/question/19526736
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Answer:
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Options:
A) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
B) Reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
D) Reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Explanation:
The null hypothesis H0: µ=43°F (a true mean temperature maintained by refrigerator is equal to 43°)
The alternative hypothesis Ha: µ<>43 (a true mean temperature maintained by refrigerator is not equal to 43).
A type II error does not reject null hypothesis H0 when it is false. Therefore, the type II error for the test fails to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Answer is in bold and i will add step
Since they are vertical angles they will be the same. Since 6=146 2=146
