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Paul [167]
3 years ago
13

What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 32 km/h and the coef

ficient of static friction between tires and track is 0.27?

Physics
2 answers:
Leviafan [203]3 years ago
5 0

Answer: 29.83m

Explanation: coefficient of friction= v^2/rg

Coefficient of friction=0.27

V=32km/h

Convert km/h to m/s

32*1000/3600

32000/3600=8.89m/s

0.27=8.89^2/r*9.81

0.27*9.81*r=79.0321

R= 79.0321/2.6487

R=29.83m

Aleksandr [31]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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Answer:

- E = 11.55J

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- If you take the capacitor as a parallel plate capacitor, you have that the energy stored on the capacitor is:

E=\frac{1}{2}CV^2=\frac{1}{2}(\frac{\epsilon_oA}{d})V^2=\frac{1}{2}\frac{\epsilon_oAV^2}{d}\\\\

A: area of the plates

d: distance between plates

If the distance between plates is increased by a factor of 4, you have:

E'=\frac{1}{2}\frac{\epsilon_oAV^2}{(4d)}=\frac{1}{4}\frac{\epsilon_oAV^2}{2d}=\frac{1}{4}E

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B = \frac{\mu\times I\times R^2}{2(R^2+Z^2)^\frac{3}{2} }

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= \frac{\mu\times I\times N}{R}\times (\frac{4}{5})^\frac{3}{2}

= 9.0 x 10^-7 NI/R

8 0
4 years ago
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