All categories

3 years ago

I really need help this was due Friday! I will mark brainiest!

Physics

1 answer:

Svetllana [295]3 years ago

6 0

Answer:

Average speed = (total distance covered) / (time to cover the distance)

You only need the first and last points from the table.

First point: Position=0, Time=0

Last point: Position= 16.34, Time = 2.34 hours

Total distance covered = 16.34 (miles ? km ?)

Time to cover the distance = 2.34 hours

Average speed = (16.34 miles) / (2.34 hours)

Average speed = 6.983 mile/hour

Explanation:

You might be interested in

A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 20

kirza4 [7]

Answer:

Energy in carriage (Potential energy) = 4,116 J

Explanation:

Given:

Mass of baby = 20 kg

Height = 21 m

Find:

Energy in carriage (Potential energy)

Computation:

The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.

In carriage accumulated energy is potential energy.

Energy in carriage (Potential energy) = mgh

Energy in carriage (Potential energy) = (20)(9.8)(21)

Energy in carriage (Potential energy) = 4,116 J

3 0

2 years ago

During several practice runs you stand at the end of a diving board and launch the basketball horizontally from a position 4.50

mr Goodwill [35]

Answer:

6.52m/s

Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem involving forces and geometries

2. Find the time that elapses from when the ball is thrown until it hits the water, this is achieved using the kinematic equation for constant acceleration and zero vertical initial velocity.

3. taking into account that the ball is launched horizontally, and that there is no horizontal acceleration, the only thing we must do is find the speed by dividing the distance traveled horizontally and dividing it by time

3 0

3 years ago

. A single strand of wire of adjustable length is wound around the circumference of a round balloon that has a diameter of 21.0

Sunny_sXe [5.5K]

Answer:

EMF = 1.1929 V

Explanation:

In this case we need to use the following expression:

EMF = B *ΔA / t (1)

Where:

B: Magnetic field

ΔA: Difference of area of the balloon

t: time

To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:

A = π r² (2)

So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)

A₁ = π * (0.105)² = 0.0346 m²

A₂ = π * (0.155)² = 0.0755 m²

Now that we have both areas, let's calculate ΔA:

ΔA = A₂ - A₁

ΔA = 0.0755 - 0.0346 = 0.0409 m²

Finally, we can determine the value of the EMF, using (1):

EMF = 1.4 * 0.0409 / 0.048

Hope this helps

6 0

2 years ago

A 6.4 kg block with a speed of 5.4 m/s collides with a 12.8 kg block that has a speed of 3.6 m/s in the same direction. After th

jenyasd209 [6]

Answer:

The velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.

Explanation:

Given;

mass of first block, m₁ = 6.4 kg

initial speed of first block, u₁ = 5.4 m/s

mass of second block, m₂ = 12.8 kg

initial speed of second block, u₂ = 3.6 m/s

final speed of second block, v₂ = 4.5 m/s

To determine the final speed of 6.4 kg block immediately after the collision, we apply principle of conservation linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

v₁ is the final speed of 6.4 kg block

v₂ is the final speed of 12.8 kg block

Substitute the given values of m₁, u₁, m₂, u₂ , v₂ and calculate v₁

6.4 x 5.4 + 12.8 x 3.6 = 6.4v₁ + 12.8 x 4.5

34.56 + 46.08 = 6.4v₁ + 57.6

80.64 = 6.4v₁ + 57.6

80.64 - 57.6 = 6.4v₁

23.04 = 6.4v₁

v₁ = 23.04 / 6.4

v₁ = 3.6 m/s

Therefore, the velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.

3 0

3 years ago

An ant is crawling up a leaf that is hangin vertically. it lifts 0:007 kg crumb up 0:12 meters. to do this, the ant exerts 0.069

Afina-wow [57]

Answer:

.000828 j

Explanation:

Work = F * d

.0069 N * .12 m = .000828 j

5 0

2 years ago