1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka [77]
3 years ago
8

How do I write a long conclusion about thanksgiving

Mathematics
2 answers:
Oksana_A [137]3 years ago
6 0

Answer:

Step-by-step explanation:

trasher [3.6K]3 years ago
4 0

Answer:

you could start by writing "In conclusion,thanksgiving is a time to give to others by handing out food and having a feast,just enjoying yourself with friends,and family! Hope this made a inspiration to others thanks for reading!"

There you go! :)

You might be interested in
Truth or Dare?<br> have a nice day
RoseWind [281]

Answer:gfgfcgfgf

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
3) Find the volume of this solid: *<br> cm<br> 2 cm
pentagon [3]

Answer:

what solid??????

Step-by-step explanation:

3 0
3 years ago
How many solutions does this equation have 10+5x/15=4
-Dominant- [34]

I think it only has One

8 0
3 years ago
The expression 1/2 H B1 + B2 use the area of a trapezoid with B1 and B2 representing the two bases length of a trapezoid and h r
Oxana [17]

Answer:

40

Step-by-step explanation:

1/2* 8 (4 + 6)  equation

4 (10)  simplify

40


7 0
3 years ago
Read 2 more answers
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
3 years ago
Other questions:
  • Is three and five a factor pair of 15
    14·2 answers
  • Which is an x-intercept of the graphed function?
    13·2 answers
  • I need help please!!!! Jon buys t shirts online for his friends. the table below shows the cost including the shipping fee. writ
    13·1 answer
  • Decimal
    9·1 answer
  • 15x + 35 = 110 whats the value of x​
    10·1 answer
  • How to multiple 90km/h x 1h 30min
    12·1 answer
  • This pentagonal right pyramid has a base area of 30 m. 5 m 7 m 8 m What is the volume of the figure?​
    10·2 answers
  • Can someone help me on this?
    10·1 answer
  • Someone please help I will mark brainliest
    10·1 answer
  • teacher gives 5 students a multiple choice test, in which each problem is worth 1 point and there is no penalty with negative po
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!