Answer: u need to use the sine and cosine law to solve for amplification
Step-by-step explanation:
Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.
B and E are both right angles.
Side BC = Side DE
<BCA =< EDA
So triangle BCA = triangle EDA
Now to the letters.
x = y - 1 Add 1 to both sides.
x + 1 = y (1)
3x - 2 = 2y + 1 Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y (2)
Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.
1.5x - 1.5 = x + 1 Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1 Add 1.5 to both sides.
0.5x = 1 + 1.5
0.5x = 2.5 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5
x = 5
Now we need a y value.
x = y - 1
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y
So the 2 sides and the 2 angles are equal when
x = 5
y = 6
C Answer <<<<<<
The answer is <span>20.3896551724</span>
The answer should be federal wage and hour law and fair labor standards act.
Answer:
g(3) = 11
g(-3) = 16
g(-1) =3
Step-by-step explanation:
For g(3)
g(x)= x² +2
g(3) = 3² + 2
g(3) = 9+2
g(3) = 11
For g(-3)
g(x) = -3x + 7
g(-3) = -3(-3) + 7
g(-3) = 9 + 7
g(-3) = 16
For g(-1)
g(x) = x² + 2
g(-1) = (-1)² +2
g(-1) = 1+2
g(-1) =3
