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3 years ago

What is the probability that the individual purchased a small cup? a cup of decaf coffee?

Mathematics

1 answer:

guapka [62]3 years ago

8 0

30% sjisizhzbs sjaisiBzbs shauauabasbsbshhasbshjasnbssjusshbssususbshsns

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2\sqrt{18}-2\sqrt{12}+2\sqrt{18}=

QveST [7]

Oh yea you can say you love me and you don’t love you baby i love mommy mama

4 0

4 years ago

Dont leave any links please

Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$

Multiply m in.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = \frac{ {m}^{2} }{ {n} } }$

Thus the answer is m^2/n.

6 0

3 years ago

Find the area of this triangle. Round to

DaniilM [7]

Answer:

63.3 square feet

Step-by-step explanation:

Let a = 20 ft, B = 15 ft, c = 9ft

$s=\frac{a+b+c}{2}$

$s=\frac{20+15+9}{2}$

$s=\frac{44}{2}$

$s=22\: ft$

$Area \: of \:\triangle = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{22(22 - 20)(22 - 15)(22 - 9)} \\ \\= \sqrt{22 \times 2 \times 7 \times 13} \\ \\= \sqrt{44 \times 91} \\ \\ = \sqrt{4,004} \\ \\ = 63.2771681 \\ \\ \approx 63.3 \: {ft}^{2}$

6 0

4 years ago

In the given figure, ray OD stands on a line AOB , ray OE and OC are the angles bisector of

Dmitry_Shevchenko [17]

Ray OE is the angle bisector of angle AOD

ray oc is the bisector of angle BOD

7 0

4 years ago

Please help!!! i really need some help on this :( I'll make you Brainliest!!!

shusha [124]

78+92=170
170/2=85

his current average is 85% so id go with C knowing that if his next quiz he got at least a 70, his average would be 80%

5 0

3 years ago