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nexus9112 [7]
3 years ago
13

Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands

on the ground above. The path of the rock can be modeled by the equation y = -0.005x2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?
Mathematics
1 answer:
kati45 [8]3 years ago
6 0
This describes a parabolic path that starts at x=0 on a value of y = -5.1.  That's when the rock is below ground in the hole.  To find the answer we need to know the second x axis crossing.  The first is when it is rising and reaches ground level, the second is after it peaks and falls back to the ground and lands. Using the quadratic formula I get the two zeros of this function to be about
x= 15.29, and 66.71.  The rock then lands 66.71 feet from him horizontally.
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3 years ago
Factor Polynomial<br> 3y^2+y-14
iris [78.8K]

Answer:

<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>

Step-by-step explanation:

<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14

<em>2. Now let us break this expression into groups:  </em>

3y^2 - 6y + 7y - 14  ⇒ ( 3y^2 - 6y )( 7y - 14 )

<em>3. Factor 3y from 3y^2 - 6y:</em>

3y^2 - 6y ⇒ 3y( y - 2 )

<em>4. Factor 7 from 7y - 14:</em>

7y - 14 ⇒ 7( y - 2 )

<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>

3y( y - 2 ) + 7( y - 2 )

<em>6. Factor common term y - 2:</em>

<em>Answer: ( y - 2 )( 3y + 7 )</em>

4 0
3 years ago
Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...​
rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

x_n = a n^4 + b n^3 + c n^2 + d n + e

From the given known values of the sequence, we have

\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}

Solving the system yields coefficients

a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4

so that the n-th term in the sequence might be

\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}

Then the next few terms in the sequence could very well be

\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of \{x_n\} eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of \{x_n\} by \Delta^{k}\{x_n\}. Then

• 1st-order differences:

\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}

• 2nd-order differences:

\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}

• 3rd-order differences:

\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}

• 4th-order differences:

\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}

From here I made the assumption that \Delta^4\{x_n\} is the constant sequence {15, 15, 15, …}. This implies \Delta^3\{x_n\} forms an arithmetic/linear sequence, which implies \Delta^2\{x_n\} forms a quadratic sequence, and so on up \{x_n\} forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0
2 years ago
Choose the correct algebraic equation to represent: the amount decreased by $9 is $42.
vichka [17]

m - 9 = 42

42 is our final answer so that should be by itself.

If something is being decreased by 9, that means that we are taking away 9 from something so it should be m - 9.

4 0
3 years ago
Read 2 more answers
A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}

We have to find the rate of increase of length.

Area of rectangle =

A = l\times w

Differentiating we get,

\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l

Putting values, we get,

8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0
3 years ago
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