Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
-1<b<7, or i suppose b.
Step-by-step explanation:
6b<42
b<7
4b+12>8
4b>-4
b>-1
Answer:
Find the X and Y Intercepts 3x-5y=-20
Find the X and Y Intercepts 3x-5y=-20. 3x−5y=−20 3 x - 5 y = - 20. Find the x-intercepts. Tap for more steps
Step-by-step explanation:
Answer: true
Step-by-step explanation:
Answer:
x=45
Step-by-step explanation:
Each triangle had 180 degrees in all and the picture shows it has a right angle. 180-90=90
90/2=45
Because there are two angles left without measurement.
