1. We assume, that the number 92.4 is 100% - because it's the output value of the task.
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 92.4 is 100%, so we can write it down as 92.4=100%. </span>
<span>4. We know, that x is 150% of the output value, so we can write it down as x=150%. </span>
5. Now we have two simple equations:
1) 92.4=100%
2) x=150%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
92.4/x=100%/150%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 150% of 92.4
92.4/x=100/150
<span>(92.4/x)*x=(100/150)*x - </span>we multiply both sides of the equation by x
<span>92.4=0.666666666667*x - </span>we divide both sides of the equation by (0.666666666667) to get x
<span>92.4/0.666666666667=x </span>
<span>138.6=x </span>
x=138.6
<span>now we have: </span>
<span>150% of 92.4=138.6</span>
Answer:
.
Step-by-step explanation:

We need to find the factors of given equation;
Solution:
On Solving the above equation we get;
Now First we will take common factor from first 2 terms which is
we get;

Now we will take the common factor from the last 2 terms which is 3 we get;

Here we get 2 terms in which
is common factor.

Hence After factorizing the given equation we get
.
*see attachment showing the two polygons in a grid.
Answer:
No, PQRST is not a scale copy of ABCDE because we the sides are not increased proportionally.
Step-by-step explanation:
A polygon can be said to be a scaled copy of another polygon, if the the same scale factor is used in scaling every segment of the preimage or original image to get the length of the corresponding segments of the scale copy or image. In order words, all segments must be scaled proportionally.
Polygon PQRST, which is the new image, has different scale factors used in scaling the various segments of the preimage. In simple terms, the sides of PQRST were not increased proportionally. Therefore, PQRST is not a scaled copy of ABCDE.
Answer:
The dimensions of the vegetable patch is 8 m by 7 m.
Step-by-step explanation:
Area of a vegetable patch is 56 square meters and the perimeter is 30 m.
If l is length and b is breadth, then area and perimeter of a rectangle is given by :


Substituting the values in the above formulas as :

and

We need to solve equation (1) and (2) to find the values of l and b such that :
Equation (2), l = 15 - b
Equation (1) becomes,

If b = 7 m, so, l = 8 m
If b = 8 m, l = 7 m
So, the dimensions of the vegetable patch is 8 m by 7 m.
Answer:
4/12
Step-by-step explanation:
i am not good at this but i will try☺