Question

The coordinates of the verticals of a rectangle are (-3,4), (7,2), (6,-3), & (-4,-1). What is the perimeter of the rectangle?

Answer 1

Answer:

30.594

Step-by-step explanation:

To find perimeter we need to find the length of all the sides

The coordinates are A(-3,4), B(7,2), C(6,-3), D (-4,-1)

To find the length of side , we use distance formula

$Distance = \sqrt{(x2-x1)^2+(y2-y1)^2}$

Side $AB =\sqrt{(7--3)^2+(2-4)^2} = \sqrt{100+4}= \sqrt{104}=10.198$

Side $BC =\sqrt{(6-7)^2+(-3-2)^2} = \sqrt{1+25}= \sqrt{26}=5.099$

Side $CD =\sqrt{(-4-6)^2+(-1--3)^2} = \sqrt{100+4}= \sqrt{104}=10.198$

Side $DA =\sqrt{(-3--4)^2+(4--1)^2} = \sqrt{1+25}= \sqrt{26}=5.099$

To find perimeter we add all the sides

10.198 + 5.099 + 10.198 + 5.099= 30.594

the perimeter of the rectangle= 30.594