$5=\frac{1}{3}(5x-15)\\ 5=\frac{5}{3}x-5\\ 5+5= \frac{5}{3}x-5 +5\\10=\frac{5}{3}x\\ 10 * 3 = 3* \frac{5}{3}x\\30=5x\\\frac{30}{5} =\frac{5}{5}x\\ 6=x\\x=6$

What did we do in this problem

we ensured that both sides remained equally balanced in value
took everything step-by-step to make sure that there were no mistakes
to check it, we can plug it back into the original equation to see if it works

$5=\frac{1}{3}(5(6)-15)\\ 5=\frac{1}{3} (30-15)\\5=\frac{1}{3}*15\\ 5=5 \checkmark\\$

Answer: x = 6

Hope that helps!

#LearnwithBrainly

5 0

1 year ago

Read 2 more answers

A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the

Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

width = 5 feet

height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

$/Hyp/^{2}$ = $/Adj 1/^{2}$ + $/Adj 2/^{2}$

$x^{2}$ = $6^{2}$ + $5^{2}$

$x^{2}$ = 36 + 25

= 61

x = $\sqrt{61}$

= 7.81

let the length of the diagonal support be represented by l. So that;

$/Hyp/^{2}$ = $/Adj 1/^{2}$ + $/Adj 2/^{2}$

$l^{2}$ = $x^{2}$ + $8^{2}$

= $\sqrt{61}$ + 64

l = $\sqrt{\sqrt{61} + 64 }$

= 61 + 8

= 69

Thus, the length of the diagonal support is 69 feet.

6 0

2 years ago

Eddi Din [679]

Answer: The relative frequency of column A in group 1= $0.75$

The relative frequency of column B in group 1= $0.25$

The relative frequency of column A in group 2= $0.56$

The relative frequency of column B in group 2= $0.44$

Step-by-step explanation:

The relative frequency is the ration of each frequency by the total value in particular group.

For group 1 : Total =102+34=136

The relative frequency of column A in group 1= $\frac{102}{136}=0.75$

The relative frequency of column B in group 1= $\frac{34}{136}=0.25$

For group 2 : Total =18+14=32

The relative frequency of column A in group 2= $\frac{18}{32}=0.5625\approx0.56$

The relative frequency of column B in group 2= $\frac{18}{32}=0.4375\approx0.44$

7 0

2 years ago