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Usimov [2.4K]
3 years ago
9

for a given speed, the distance traveled varies directly with the time. Kate's school is 5 miles away from her home and it takes

her 10 minutes to reach the school. If Josh lives 2 miles from school and travels at the same school as Kate, how long will it take him to reach the school?​
Mathematics
2 answers:
Yuri [45]3 years ago
7 0

Answer: It will take Josh 4 minutes to get to school.

Step-by-step explanation:

  1. Divide the distance by the time.
  2. So, 10 minutes/ 5 miles
  3. Solve: 10/5= 2
  4. Their speed is 2 minutes per mile.
  5. Multiply 2 miles by 2 minutes
  6. The answer is 4 minutes
  7. It takes 4 minutes to get from Josh's house to the school.

      (;

Allisa [31]3 years ago
6 0

Answer:

  4 minutes

Step-by-step explanation:

Since the rates are the same, we have the proportion ...

  (Josh's time)/(Josh's distance) = (Kate's time)/(Kate's distance)

Solving for Josh's time, we get ...

  Josh's time = (Kate's time)(Josh's distance)/(Kate's distance)

  Josh's time = (10 minutes)(2 miles)/(5 miles)

  Josh's time = (10·2)/5 minutes = 4 minutes

It will take Josh 4 minutes to reach the school.

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Step-by-step explanation:

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7 0
2 years ago
Jean and Jericho who are playing in the school grounds decided to sit on a
Natalija [7]

We want to see underline the correct part in each statement.

  • 1) This situation illustrates (direct, <u>inverse</u>) variation.
  • 2) The two quantities that must vary in this situation are (<u>weight and </u>
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  • 4) When Jean moves farther from the center, Jericho tends to go (up,
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So, Jean and Jericho are playing on a seesaw.

Jean is heavier than Jericho.

Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.

If we define:

  • W₁ = Jean's weight.
  • d₁ = Jean's distance to the center.
  • W₂ = Jericho's weight.
  • d₂ = Jericho's distance to the center.

We must have:

W₁*d₁ = W₂*d₂

Then:

1) This situation illustrates (direct, <u>inverse</u>) variation.

d₁, the position of Jean, varies inversely with respect to Jean's weight.

2) The two quantities that must vary in this situation are (<u>weight and </u>

<u>distance from the center</u>, height and weight).

(by the equation above)

3) The heavier the kid, the (<u>closer</u>, farther) he/she should be at the

center to balance the seesaw?

By the given equation, we see that d₁ must be smaller than d₂.

And the last two are trivial:

4) When Jean moves farther from the center, Jericho tends to go (up,

<u>down</u>).

5) If Jericho moves closer to the center, Jean tends to go (up, <u>down</u>).

If you want to learn more, you can read:

brainly.com/question/18320907

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2 years ago
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Answer:

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Step-by-step explanation:

There is a graphing calculator called desmos that can help you answer questions like this, but, if you don't want to use that, you can just make a graph and imagine the transformation. Remember, when you reflect something over an axis, it is like you are folding the graph along the axis and your new point will be on the other side.

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sesenic [268]

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