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IRINA_888 [86]
2 years ago
6

The following diagram shows part of the graph of the function f(x)= -12x + 26 and g(x) = -(1/5) ^ -x + 2 + 3 what are the soluti

ons of the equation -12 x + 26 = -(1/5) -x + 2 + 3
A. x = -22 and x = 3
B. x = 2 and x = 3
C. x = 2 and x = -22
D. x = 2 and x = 4

Mathematics
1 answer:
Nina [5.8K]2 years ago
6 0
The answer would be D. For you to find the solution you would need to look at the x from the coordinates.
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PLEASE HURRY!!!!!!!
Paraphin [41]

Answer:

I am guessing Point D is the point in the middle of the rectangle.

x = 7.5

Step-by-step explanation:

DV is half of 66

DV = 33

33/4.4 = 7.5

7 0
3 years ago
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
ANSWER TO THE QUESTION............
olga55 [171]
I’m sorry but I can’t see it. Message me the licture
3 0
3 years ago
The aquarium has 3 more yellow fish than green fish. 60 percent of the fish are yellow. How many green fish are in the aquarium?
cupoosta [38]

The aquarium has 3 more yellow fish than green fish.

60% of the fish are yellow.

To find:

How many green fish are in the aquarium?

Step-by-step explanation:

Let there be x number of fish in the aquarium.

60% of the fish are yellow.

So there are 60x/100 = 3x/5 yellow fish.

Then (100 - 60)% = 40% fish are green.

So there are 40x/100 = 2x/5 green fish.

Given that, there are 3 more yellow fish than green fish

⇒ 3x/5 = 2x/5 + 3

⇒ 3x/5 = (2x + 15)/5

⇒ 3x = 2x + 15

⇒ 3x - 2x = 15

⇒ x = 15

Now, 2x/5 = 2/5 × 15 = 2 × 4 = 6

Answer:

There are 6 green fish in the aquarium.

5 0
2 years ago
Explain how to find the difference between 9^10/9^11 and 9^11/9^10
kkurt [141]

Answer:

jhv

Step-by-step explanation:

kjbb

6 0
2 years ago
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