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DIA [1.3K]
3 years ago
8

Having trouble on this

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

The answer is the first one

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A car averages 30 miles of driving for 1 gallon of gas if the car holds 12 gallons how many times will we have to fill up his ga
icang [17]

Answer:

7 times

Step-by-step explanation:

30 miles per 1 gallon

Car holds 12 gallons

30x12=360

2520/360=7

3 0
4 years ago
Read 2 more answers
In 1987​, 522 comma 000 people worked in the air transportation industry. In 2003​, the number was 480 comma 000. ​(a) Find a li
umka2103 [35]

Answer:

the linear equation is :

y= -2625x+5737875

and 440000 employees will be in year 2271

Step-by-step explanation:

in order to find the linerar equation let us first convert the given data into (x,y ) co-ordinates i.e

x1= 1987 y1= 522,000  

and

 

x2= 2003, y2 = 480000

according to two point form:

y-y1 = (y2-y1) \frac{x-x1}{x2-x1}

In this example we have x1=1987 , y1=522000 , x2=2003 and y2=480000. So,

y - 522000 = \frac{480000-522000}{2003-1987}  (x-1987)\\y- 522000 = -2625(x-1987)\\y- 522000= -2625x+5215875\\\\y= -2625x+5737875

now to find the year when there will be 440000 employs working , we simply put y= 440000 in the above derived equation

440000= -2625x+ 5737875\\\\2526x = 5737875 -440000\\2526x =  5736555\\x= \frac{5736555}{2526} \\x= 2271

7 0
3 years ago
I'm awful at word problems someone please help
Lubov Fominskaja [6]

Your answer is B.

Flat fee is $250, so we cannot change this number.
585 - 250 = 335
335 (remaining cash) divided by 8 (price per student) = 41.875
Since we can't bring .8 of one student on the trip, we will round the number down to 41, because if we round up we will go over the budget of $585.

The maximum number of students a school can send is 41.
6 0
3 years ago
Read 2 more answers
For a standard normal distribution,Find P(-1.21 < Z< 2.26)
Mars2501 [29]

Answer:

The range of z-score is given below as

P(-1.21Using a graphing calculator, we will have the image be[tex]\begin{gathered} P(z

4 0
1 year ago
determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
2 years ago
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