1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dmitriy555 [2]
3 years ago
12

Across how many lines of reflection can you reflection can you reflect a square onto itself

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

one line of reflection is all you need to reflect a square onto itself


You might be interested in
/viewform?hr submission=Chclk4feKBIQ.
Gennadij [26K]

Answer:

c) .22

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 2.5, n = 500

Then

M = z*\frac{\sigma}{\sqrt{n}}

M = 1.96*\frac{2.5}{\sqrt{500}}

M = 0.22

5 0
3 years ago
1/3 of 3/4 = ____ fourth(s)
SashulF [63]

Answer:

0.99

Step-by-step explanation:

.33 x .75 = .2475 or 0.99/4

6 0
2 years ago
What is the area, in square units, of trapezoid AEDC shown below?
just olya [345]
20 • 12 is 240
1/2 • 12 • 4 is 24
so 264
7 0
3 years ago
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the larg
katovenus [111]
Problema Solution

You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?

Answer provided by our tutors

Make a drawing and denote:


x = half of the length of the enclosure


2x = the length of the enclosure


y = the width of the enclosure


P = 800 ft the perimeter


The perimeter of the two enclosures can be expressed P = 4x + 2y thus


4x + 3y = 800


Solving for y:

........

click here to see all the equation solution steps

........

y = 800/3 - 4x/3


The area of the two enclosure is A = 2xy.


Substituting y = 800/3 - 4x/3 in A = 2xy we get


A = 2x(800/3 - 4x/3)


A =1600x/3 - 8x^2/3


We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum: 


x max = -b/2a, a = (-8/3), b = 1600/3


x max = (-1600/3)/(2*(-8/3))


x max = 100 ft


y = 800/3 - 4*100/3


y = 133.33 ft


2x = 2*100


2x = 200 ft

3 0
3 years ago
(6x² + 36x² + 12) ÷ (x+6)
astra-53 [7]

Answer:

=42x2+1

Step-by-step explanation:

6x2+36x2+12x+6

=42x2+1

8 0
3 years ago
Other questions:
  • Is 28 a solution to the inequality you wrote in Exercise 3? How do you know?
    11·1 answer
  • Four times the sum of a number and eight times the number is 252. Find number
    7·1 answer
  • A tessellation is the regular _____ of a plane shape.
    12·1 answer
  • What is 10/9 ? 9/8 closer to 0,1/2,1
    12·1 answer
  • 2x-7y=-56 and 7x+2y=8 are they parallel perpendiculare or neither
    13·2 answers
  • 7. Approximately 9 out of 100 people are left handed. Out of a population of 1740 people. How man are likely o be left
    10·1 answer
  • What is the slope intercept form of the perpendicular line to the line with (-2,7), (0,1) and (2,-5) points
    10·1 answer
  • What is the answer???????????​
    6·1 answer
  • Determine the three-decimal digit approximation of the number v17.
    10·1 answer
  • Can you help me solve 4x - 15 = 17 - 4x
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!