All categories

2 years ago

02119a rectangular pool is 7 feet wide. it is 3 Times as long as it is wide

Mathematics

1 answer:

marshall27 [118]2 years ago

5 0

What are you looking for?? Area? Perimeter?

You might be interested in

<img src="https://tex.z-dn.net/?f=solve%20%3A%20%20-%20%20%5C%5C%20%20%5C%5C%20%282%20%5E%7B2%7D%20%20%2B%204%20%7B%7D%5E%7B2%7D

Dahasolnce [82]

$\implies {\blue {\boxed {\boxed {\purple {\sf {20}}}}}}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}$

$= ( {2}^{2} + {4}^{2} )$

$= [(2 \times 2) + (4 \times 4)]$

$= (4 + 16)$

$= 20$

$\large\mathfrak{{\pmb{\underline{\orange{Thank\:you! }}{\orange{❦}}}}}$

8 0

2 years ago

Convert 2x+5y=-3 into y=mx+b form

GalinKa [24]

5y = -2x-3
y= -2x/5 - 3/5

6 0

3 years ago

ICE Princess25 [194]

Answer:

5 x 8 /a*7

Step-by-step explanation:

8 0

2 years ago

What is the slope of the line with points (-5, -4) and (2, 7)?

jolli1 [7]

Answer:

m = 11/7

Step-by-step explanation:

m = y2-y1/x2-x1

m = 7-(-4)/2-(-5)

m = 7+4/2+5

m = 11/7

6 0

2 years ago

Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?

monitta

Answer:

$(x-7)^2+(y-2)^2=34$

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (7, 2), h = 7 and k = 2. Substitute:

$(x-7)^2+(y-2)^2=r^2$

Next, the since a point on the circle is (2, 5), y = 5 when x = 2. Substitute:

$(2-7)^2+(5-2)^2=r^2$

Solve for r:

$(-5)^2+(3)^2=r^2$

Simplify. Thus:

$25+9=r^2$

Finally, add:

$r^2=34$

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

$(x-7)^2+(y-2)^2=34$

4 0

2 years ago