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Kryger [21]
2 years ago
9

Help me pleaseeeeeee

Mathematics
2 answers:
Tresset [83]2 years ago
6 0
4th one is the answer
e-lub [12.9K]2 years ago
5 0
The answer is Radius
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Evaluate: 16 - 2+3 - 4
natulia [17]

Answer: 13

Step-by-step explanation:

Following order of operations:

16-2+3-4

14+3-4

17-4

13

8 0
3 years ago
Read 2 more answers
I don’t know the answer I’m not that smart help<br><br>Thank you
Stolb23 [73]

Answer:

H

Step-by-step explanation:

The tiny squares equal to 12 already so it is already greater therefore x=0

6 0
3 years ago
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57tan(27.32^0)

h\approx8.45 ft

Thus, the height of the statue is approximately, 8.45 feet.

3 0
3 years ago
Write the factor pairs for 46​
Natali5045456 [20]
• Factors of 46 =1, 2, 23, 46.

• Distinct Factors of 46 = 1, 2, 23, 46.
3 0
3 years ago
Find cos theta if sin theta=3/4 and theta lies in quadrant 2
GaryK [48]
By the Pythagorean theorem, the missing side is -sqrt7. The definition of sin is side opposite over hypotenuse, so go into Q2 and make an angle and label the side opposite the angle with a 3 and the hypotenuse a 4. The other leg is -sqrt7 cuz x is negative in Q2. The cosine of an angle is the side adjacent over the hypotenuse, so the cos then is -sqrt7/4
7 0
2 years ago
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