How many triangles can be constructed with angles measuring 10º, 80º, and 90º?
2 answers:
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Answer:
Option B (1,10)
Step-by-step explanation:
we have
we know that
If a ordered pair is on the graph of f(x) then the ordered pair must satisfy the function f(x)
<u><em>Verify each case</em></u>
case A) (0,0)
For x=0
Compare the value of f(x) with the y-coordinate of the ordered pair
therefore
The ordered pair is not on the graph of f(x)
case B) (1,10)
For x=1
Compare the value of f(x) with the y-coordinate of the ordered pair
therefore
The ordered pair is on the graph of f(x)
case C) (0,10)
For x=0
Compare the value of f(x) with the y-coordinate of the ordered pair
therefore
The ordered pair is not on the graph of f(x)
case D) (10,1)
For x=10
Compare the value of f(x) with the y-coordinate of the ordered pair
therefore
The ordered pair is not on the graph of f(x)
Equation B is written in vertex form, which means you can read the vertex (extreme value) from the numbers in the equation.
Vertex form is
y = a(x -h)² + k
where the vertex (extreme point) is (h, k). Whether that is a maximum or a minimum depends on the sign of "a". When "a" is negative, the graph is a parabola that opens downward, so the vertex is a maximum.
Equation B reveals its extreme value without needing to be altered.
The extreme value of this equation is a maximum at the point (2, 5).
Vertex form is
y = a(x -h)² + k
where the vertex (extreme point) is (h, k). Whether that is a maximum or a minimum depends on the sign of "a". When "a" is negative, the graph is a parabola that opens downward, so the vertex is a maximum.
Equation B reveals its extreme value without needing to be altered.
The extreme value of this equation is a maximum at the point (2, 5).
