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labwork [276]
3 years ago
13

Which of the following is a factor of 10x2 − 19x 6? 5x − 3 5x − 2 2x 1 none of the above

Mathematics
2 answers:
kati45 [8]3 years ago
7 0
I believe the correct answer from the choices listed above is the fourth option. The factor of the expression given as <span>10x^2 − 19x^6 would be 1 only. None of the other choices would factor correctly the expression. Hope this answers the question. Have a nice day.</span>
balandron [24]3 years ago
3 0

Answer:5x-2

Step-by-step explanation:

Did the test

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Please help!! i will mark you brainliest!!!
aniked [119]

Answer:

A- 5 meters in 0.1 seconds

Step-by-step explanation:

M/s means meters in 1 second and A says 5 meters in 1 second

7 0
3 years ago
(b) Only one of the sets can contain all five correct answers. If you are guessing, so that you are as likely to choose one sequ
shepuryov [24]

Solution :

Given that there is only one set which can contain all the five correct answers. While guessing that I am likely to choose only one sequence of the answers as another, then the probability of getting all the five answers correct  is given by :

Given : X \sim binomial $\left( 5 , \frac{1}{3} \right)$

P (X = 5)

$= \ ^5C_5\left({\frac{1}{3}\right)^5\left(\frac{2}{3}\right)^0$

= 0.00412

Thus the probability is 0.00412

8 0
3 years ago
Which is true about an equilateral triangle?
Keith_Richards [23]

Answer: all angle measures are equal

6 0
3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 2000 years?
Assoli18 [71]

Answer:

167.27 mg.

Step-by-step explanation:

We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.

We will use half life formula to solve our given problem.

N(t)=N_0*(\frac{1}{2})^{\frac{t}{t/2}, where N(t)= Final amount after t years, N_0= Original amount, t/2= half life in years.

Now let us substitute our given values in half-life formula.

N(2000)=400*(\frac{1}{2})^{\frac{2000}{1590}

N(2000)=400*(0.5)^{1.2578616352201258}    

N(2000)=400*0.4181633028874878239

N(2000)=167.26532115499512956\approx 167.27

Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.

3 0
3 years ago
Solve 2 | 2x + 10|+ 4 &gt; 10
Valentin [98]

Answer:

x>−72 or x<−132

Step-by-step explanation:

I believe that is the answer

8 0
4 years ago
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