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Darya [45]
2 years ago
6

Describe how the shape moves from:

Mathematics
1 answer:
dedylja [7]2 years ago
6 0

Answer:

1. Frame 1 to Frame 2 - Vertical downward translation

2. Frame 2 to Frame 3 - 90^{0} counterclockwise rotation

3. Frame 3 to Frame 4 - Vertical upward translation

Step-by-step explanation:

The movement of the shapes from one frame to the other can be described by solid transformations. These are procedures required to change the orientation or size of a given shape. They include: rotation, translation, dilation and reflection.

1. When the shape in frame 1 is translated vertically downwards, it would produce the shape in frame 2.

2. Rotating the shape in frame 2 by 90^{0} counterclockwise would move it to the shape in frame 3.

3. Vertical upward dilation would move the shape in frame 3 to that in frame 4.

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Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
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Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

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Step-by-step explanation:

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