Answer:
-11.167 is the answrr
Step-by-step explanation:
Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.
For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.
<h3>What is the binomial distribution formula?</h3>
The formula is:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- A survey showed that 77% of us need correction, hence p = 0.77.
- 13 adults are randomly selected, hence n = 13.
The probability that at least 12 of them need correction for their eyesight is given by:
![P(X \geq 12) = P(X = 12) + P(X = 13)](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%2012%29%20%3D%20P%28X%20%3D%2012%29%20%2B%20P%28X%20%3D%2013%29)
In which:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299](https://tex.z-dn.net/?f=P%28X%20%3D%2012%29%20%3D%20C_%7B13%2C12%7D.%280.77%29%5E%7B12%7D.%280.23%29%5E%7B1%7D%20%3D%200.1299)
![P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334](https://tex.z-dn.net/?f=P%28X%20%3D%2013%29%20%3D%20C_%7B13%2C13%7D.%280.77%29%5E%7B13%7D.%280.23%29%5E%7B0%7D%20%3D%200.0334)
Then:
![P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%2012%29%20%3D%20P%28X%20%3D%2012%29%20%2B%20P%28X%20%3D%2013%29%20%3D%200.1299%20%2B%200.0334%20%3D%200.163)
The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.
More can be learned about the binomial distribution at brainly.com/question/24863377
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h + j ;
2)
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;
3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j - h ;
4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
If the companies claim is to be true this statement would also be true. Since the child bag is halved in the amount of the adults, the percentage would double. There are both 15 red jelly beans in each bag. 15% of 100 is 15. 30% of 50 is 15.