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AnnyKZ [126]
3 years ago
10

You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed

the ride can go at?
Physics
1 answer:
Citrus2011 [14]3 years ago
8 0

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

a=1.1 g

where g=9.8 m/s^2 is the acceleration of gravity. Substituting,

a=(1.1)(9.8)=10.8 m/s^2

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

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The magnitude of that other charge will be 9×10⁻⁵ C. The force on the charge is inverse of the distance.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The magnitude of that other charge is found as;

\rm F = \frac{Kq_1q_2}{r^2} \\\\ \rm 9  = \frac{9 \times 10^9 \times 1\times 10^{-4}\times q_2}{(3)^2} \\\\ q_2=9\times 10^{-5} \ C

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If a car is moving to the left with constantvelocity, one can conclude that
jeka94

Answer:

The net force applied to the car is zero.

Explanation:

We are given that a car is moving to the left with constant velocity.

When the car moving with constant velocity

Then, the final velocity=Initial velocity

Change in velocity=Final velocity- initial velocity=0

When change in velocity is zero then , acceleration of car

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Force=Mass\times acceleration=Mass\times 0=0

The net force applied on the car will be zero.

Option C:The net force applied to the car is zero.

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