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Ber [7]
4 years ago
9

What does solution mean in science

Physics
2 answers:
slega [8]4 years ago
8 0
A solution is a mixture composed of two or more substances which is always homogeneous. One substance dissolves in with the other substance making a solution.

Hope this helps!
Pavlova-9 [17]4 years ago
8 0
A liquid mixture in which the minor component is uniformly distributed within the major component
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6. According to Ohm's Law, current (I), voltage (V), and resistance (R)
SIZIF [17.4K]

Answer: C

Explanation: according to the law voltages = to current and resistance

7 0
3 years ago
A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative
Liula [17]

Question is missing. Found on google:

a) What are the components of the acceleration of the fish?  

(b) What is the direction of its acceleration with respect to unit vector î?

(c) If the fish maintains constant acceleration, where is it at t = 30.0 s?

(a) (0.73, -0.47) m/s^2

The initial velocity of the fish is

u=(4.00 i + 1.00 j) m/s

while the final velocity is

v=(15.0 i - 6.00 j) m/s

Initial and final velocity are related by the following suvat equation:

v=u+at

where

a is the acceleration

t is the time

The time in this case is t = 15.0 s, so we can use the previous equation to find the acceleration, separating the components:

v_x = u_x + a_x t\\a_x = \frac{v_x-u_x}{t}=\frac{15.0-4.00}{15.0}=0.73 m/s^2

v_y = u_y + a_y t\\a_y = \frac{v_y-u_y}{t}=\frac{-6.00-1.00}{15.0}=-0.47 m/s^2

(b) -32.8^{\circ}

The direction of the acceleration vector with respect to i can be found by using the formula

\theta = tan^{-1}(\frac{a_y}{a_x})

where

a_x is the horizontal  component of the acceleration

a_y is the vertical component of the acceleration

From part a), we have

a_x = 0.73 m/s^2

a_y = -0.47 m/s^2

Substituting,

\theta = tan^{-1}(\frac{-0.47}{0.73})=-32.8^{\circ}

(c) r=(460.5 i - 185.1 j )m

The initial position of the fish is

r_0 = (12.0 i -3.60 j) m

The generic position r at time t is given by

r= r_0 + ut + \frac{1}{2}at^2

where

u=(4.00 i + 1.00 j) m/s is the initial velocity

a=(0.73 i -0.47 j) m/s^2 is the acceleration

Substituting t = 30.0 s, we find the final position of the fish. Separating each component:

r_x =12.0 + (4.00)(30) + \frac{1}{2}(0.73)(30)^2=460.5 m\\r_y = -3.60 + (1.00)(30) + \frac{1}{2}(-0.47)(30)^2=-185.1 m

So the final position is

r=(460.5 i - 185.1 j )m

4 0
3 years ago
Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 940 km/hr above East Lansing. The
ANTONII [103]

Answer:

option (b)

Explanation:

B = 0.7 x 10^-4 T

v = 940 km/h = 940 x 5 / 18 = 261.11 m /s

l = 60 m

Th emotional emf is given by

e = B v l

e = 0.7 x 10^-4 x 261.11 x 60 = 1.096 V

e = 1.1 V

5 0
3 years ago
A woman wears bifocal glasses with the lenses 2.0 cm in front of her eyes. The upper half of each lens has power-0.500 diopter a
saveliy_v [14]

Answer:

q = -2 m  and  q = -0.5 m

Explanation:

For this exercise we must use the equation of the optical constructor

        1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and the image, respectively

Let's start with the far vision point, in this case the power of the lens is

        P = -0.5D

power is defined as the inverse of the focal length in meter

      f = 1 / D

      f = -1 / 0.5

      f = - 2m

the object for the far vision point is at infinity p = infinity

     1 / f = 1 / p + i / q

      1 / q = 1 / f - 1 / p

      1 / q = -1/2 - 1 / ∞

       q = -2 m

The sign indicates that the image is on the same side as the object

Now let's lock the near view point

D = +2.00 D

f = 1 / D

f = 0.5m

the near mink point is p = 25 cm = 0.25 m

        1 / f = 1 / p + 1 / q

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 0.5 - 1 / 0.25

        1 / q = -2

        q = -0.5 m

the sign indicates that the image is on the same side as the object in front of the lens

8 0
4 years ago
A person catches a ball with a mass of 145 g dropped from a height of 60.0 m above his glove. His hand stops the ball in 0.0100
natita [175]

Answer:

870N

Explanation:

momentum techniques

7 0
4 years ago
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