Answer:
0.4
Explanation:
F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.
Since the mass is moving with a constant velocity, there's no acceleration hence
where N is the weight of object and \mu is coefficient of kinetic friction.
the subject

Substituting F for 8 N and N for 20 N

Therefore, coefficient of kinetic friction is 0.4
Answer:
When all the electrons are removed from an atom, it becomes something as a positively charged particles also known as alpha particles.
<u>Explanation:
</u>
The bare nucleus which is positively charged help in scattering experiments as it has high penetrating powers. <em>An atom is made up of electrons, protons and neutrons. We need huge energy to separate the electrons from their parent atom, still making it separated brings you a particle with a positive charge and only mass having high penetrating power.
</em>
Answer:
Impulse = 80Ns
Explanation:
Given the following data;
Mass = 3kg
Force = 20N
Time = 4 seconds
To find the impulse experienced by the object;
Impulse = force * time
Impulse = 20*4
Impulse = 80Ns
Therefore, the impulse experienced by the object is 80 Newton-seconds.
Yes, an object can have both of these at the same time. Potential energy is energy that is stored in an object. Kinetic energy is the energy that is associated with motion. So what you have to have is an object that is in motion but still has more energy that it has yet to convert into kinetic energy.
To solve this problem we will apply the concepts related to pressure, depending on the product between the density of the fluid, the gravity and the depth / height at which it is located.
For mercury, density, gravity and height are defined as



For the air the defined properties would be



We have for equilibrium that


Replacing,

Rearranging to find 


Therefore the elevation of the mountain top is 9400ft