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Vika [28.1K]
3 years ago
5

The average radial velocity of galaxies in the Hercules cluster is 10,800 km/s. (a) using H0 = 73 km/s/Mpc, find the distance to

the Hercules cluster in Mpc. (b) How would your answer to (a) differ if the Hubble constant had a smaller value?
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

a) 147.95 Mpc

Explanation:

Using Hubble's formula

v = H_od

where;

v = radical velocity

H_o = Hubble's constant

d = distance

Given that:

The average radial velocity of galaxies in the Hercules cluster v =  10,800 km/s

Also using H_o = 73 km/s/ Mpc ; we  make distance d the subject of the formula:

Then distance d can be written as:

d = \frac{v}{H_o}

d = \frac{10,800  \ km/s}{73 \ km/s/Mpc}

d = 147.95 Mpc

b)

Now, if the Hubble constant had a smaller value, then for a  given velocity the distance to the galaxy will increase because distance d is inversely proportional to H_o

i.e  

d  ∝ \frac{1}{H_0}

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