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pychu [463]
3 years ago
8

Given that D is the midpoint of AB and B is the midpoint of AC, which statement must be true?

Mathematics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

AC =4DB

Step-by-step explanation:

D is midpoint of AB .So, AD = DB

AB = 2DB ---------- (i)

B is the midpoint of AC.So, AB = BC

AC = 2AB

= 2*2DB     {FROM 1}

=4DB  

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Answer:

A. It would become a different atom.

C. Its charge would increase by 1

Step-by-step explanation:

Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

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Can someone please help me in one of these!?
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Answer:

9) y = -200x + 1200

11) slope = -2

15) $2,450

16) 9 days

Step-by-step explanation:

9) Given the two points from the graph:

Let (x₁, y₁) = (0, 1200)

(x₂, y₂) =  (1, 1000)

Substitute these values into the following slope formula:

m = (y₂ - y₁)/(x₂ - x₁)

m = (1000 - 1200)/(1 - 0)

m = -200/1

m = -200

The slope of the line is -200.

Next, we need to determine the y-intercept, which is the point on the graph where it crosses the y-axis. Upon observing the graph, it shows that the line crosses at point (0, 1200). The y-coordinate of this ordered pair is the value of the y-intercept, b = 1200.

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<h3>11) Given the points, (5, -18) and (-4, 0): </h3>

Let (x₁, y₁) =(5, -18)

(x₂, y₂) =  (-4, 0)

Substitute these values into the following <u>slope formula</u>:

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{0 - (-18)}{-4 - 5} = \frac{0 + 18}{-9} = -2

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<h3>15) Solve:</h3>

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y = 150x + 200

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x = number of hours worked.

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y = 150x + 200

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ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

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We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

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\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

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=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

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